nomer 7,8,9
pake cara yhh supaya aku paham gmana ngerjain nya
Penjelasan dengan langkah-langkah:
[tex]7. \: {( \frac{ {x}^{ \frac{2}{3} } {y}^{ - \frac{4}{3} } }{ {y}^{ \frac{2}{3} } {x}^{2} } )}^{ - \frac{3}{4} } \\ = ({x}^{ \frac{2}{3} - 2 } {y}^{ - \frac{4}{3} - \frac{2}{3} } )^{ - \frac{3}{4} } \\ = ({x}^{ - \frac{4}{3} } {y}^{ - \frac{6}{3} } )^{ - \frac{3}{4} } \\ = {x}^{ - \frac{4}{3} ( - \frac{3}{4}) } {y}^{ - \frac{6}{3}( - \frac{3}{4} ) } \\ = {x}^{ \frac{12}{12} } {y}^{ \frac{18}{12} } \\ = x {y}^{ \frac{3}{2} } = x {y}^{ \frac{2}{2} } \times {y}^{ \frac{1}{2} } \\ = xy \sqrt{y} \: (e)[/tex]
[tex]8. \: \frac{3}{2 + \sqrt{3} } \\ = \frac{3}{2 + \sqrt{3} } \times \frac{2 - \sqrt{3} }{2 - \sqrt{3} } \\ = \frac{3(2 - \sqrt{3}) }{(2 + \sqrt{3} )(2 - \sqrt{3} )} \\ = \frac{6 - 3 \sqrt{3} }{4 - 2 \sqrt{3} + 2 \sqrt{3} - 3 } \\ = \frac{6 - 3 \sqrt{3} }{1} \\ = 6 - 3 \sqrt{3} \\ = 3(2 - \sqrt{3} ) \: (b)[/tex]
[tex]9. \: \frac{ \sqrt{2} - \sqrt{3} }{ \sqrt{2} + \sqrt{3} } = \frac{ \sqrt{2} - \sqrt{3} }{ \sqrt{2} + \sqrt{3} } \times \frac{ \sqrt{2} - \sqrt{3} }{ \sqrt{2} - \sqrt{3} } \\ = \frac{( \sqrt{2} - \sqrt{3} )( \sqrt{2} - \sqrt{3}) }{( \sqrt{2} + \sqrt{3} )( \sqrt{2} - \sqrt{3} )} \\ = \frac{2 - \sqrt{6} - \sqrt{6} + 3 }{2 - \sqrt{6} + \sqrt{6} - 3} \\ = \frac{5 - 2 \sqrt{6} }{ - 1} \\ = - (5 - 2 \sqrt{6} ) \\ = 2 \sqrt{6} - 5 \: (e)[/tex]
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